A bag contains 13 balls numbered from 1 to 13. Suppose drawing of an even number is a success. Two balls are drawn with replacement from the bag. The probability of getting two successes is

$\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{balls} = 13$

$\text{ even numbers from 1 to 13 }=\{2,4,6,8,10,12\}$

$\mathrm{Probability} \mathrm{of} \mathrm{getting} \mathrm{even} \mathrm{numbered} \mathrm{ball} \mathrm{is} \mathrm{p}=\frac{6}{13}$

Two balls are drawn with replacement from the bag. 

$\mathrm{The} \mathrm{probability} \mathrm{of} \mathrm{getting} \mathrm{two} \mathrm{successes} \mathrm{isP}(\mathrm{X}=2)=\frac{6}{13}\left(\frac{6}{13}\right)=\frac{36}{169}$