A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?

 No. of red balls = 5 and  No. of black balls = 3

The total number of balls = 5 + 3 = 8

We know that

P(E) = (Number of favorable outcomes/ Total number of outcomes)

(i) Probability of drawing red balls 

 P (red balls) = (no. of red balls/total no. of balls) 

= 3/8

(ii) Probability of drawing black balls 

 P (black balls) = (no. of black balls/total no. of balls) 

= 5/8