A bag contains $$3$$ red balls and $$5$$ black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?

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Infinity Learn · Accepted Answer

No. of red balls $$=$$ $$5$$ and  No. of black balls $$=$$ $$3The$$ total number of balls $$=$$ $$5$$ $$+$$ $$3$$ $$=$$ $$8We$$ know $$thatP(E)$$ $$=$$ (Number$$ of favorable $$outcomes/$$ Total number of $$outcomes)(i) Probability of drawing red balls  P (red$$ $$balls) $$=$$ (no$$. of red $$balls/total$$ no. of $$balls) $$=$$ $$3/8(ii)$$ Probability of drawing black balls  P (black$$ $$balls) $$=$$ (no$$. of black $$balls/total$$ no. of $$balls) $$=$$ $$5/8$$

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?

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