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A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?

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detailed solution

Correct option is A

 No. of red balls = 5 and  No. of black balls = 3

The total number of balls = 5 + 3 = 8

We know that

P(E) = (Number of favorable outcomes/ Total number of outcomes)

(i) Probability of drawing red balls 

 P (red balls) = (no. of red balls/total no. of balls) 

= 3/8

(ii) Probability of drawing black balls 

 P (black balls) = (no. of black balls/total no. of balls) 

= 5/8

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detailed solution

Correct answer is 1

 No. of red balls = 5 and  No. of black balls = 3

The total number of balls = 5 + 3 = 8

We know that

P(E) = (Number of favorable outcomes/ Total number of outcomes)

(i) Probability of drawing red balls 

 P (red balls) = (no. of red balls/total no. of balls) 

= 3/8

(ii) Probability of drawing black balls 

 P (black balls) = (no. of black balls/total no. of balls) 

= 5/8

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?

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