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A bag contains a number of marbles of which $80$ are red, $24$ are white and the rest are blue. If the probability of randomly selecting a blue marble from this bag is $\frac{1}{5}$ , how many blue marbles are there in the bag?

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25

26

27

28

answer is B.

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Detailed Solution

Given, a bag contains 80 red, 24 white and the rest blue marbles, the probability of randomly selecting a blue marble from this bag is

\frac{1}{5}

.
The Probabaility of red marble is

P (E) = \frac{1}{5}

\frac{1}{5} = \frac{blue}{red + blue + white}

\frac{1}{5} = \frac{blue}{80 + 24 + blue}

104 + blue = 5 blue

we get,

4 blue = 104

blue = 26

Thus, there are 26 blue marbles in the bag.
Therefore, option (2) is correct.

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