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Q.

A bag initially contains 1 red and 2 blue ball. An experiment consisting of selecting a ball at random noting its colour and replacing it together with an additional ball of the same colour. If three such trails are made, then

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a

Probability that at least two blue ball is drawn is 0.9

b

Probability that exactly one blue ball is drawn is 0.2

c

Probability that all the drawn balls are red given that all the drawn balls are of same colour is 0.2

d

Probability that at least one red ball is drawn is 0.6

answer is A, B, C, D.

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Detailed Solution

(1) P (drawing at least 1 blue) = 1- P (RRR)
$= 1 - (\frac{1}{3}) (\frac{2}{4}) (\frac{3}{5})$ By given
condition $= 1 - \frac{1}{10} = \frac{9}{10} = 0 .9$
(2) P(RRB) + P(RBR) + P(BRR) = 0.2
(3) $P [\frac{(RRR)}{(RRR) \cup (BBB)}] = 0 .2$
(4) P(at least in red) = 1–P (no red)=1–P(BBB)=0.6

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