A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of mass 200g travelling with a speed of $10 m s^{- 1}$ gets embedded in it, then loss of kinetic energy will be

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4.9 J

9.8J

14.7J

19.6J

answer is B.

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Detailed Solution

As no external force is acting on system so, $P_{i} = P_{f}$

$0.2 \times 10 = 10 \times v \Rightarrow v = 0.2 m / \sec$

$L o s s i n K . E . = \frac{1}{2} \times (0.2) \times 10^{2} - \frac{1}{2} \times 10 {(0.2)}^{2} = \frac{1}{2} \times 10 \times (0.2) [10 - 0.2] = 9.8 J$

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