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Q.

A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 ms^-1 gets embedded in it, then loss of kinetic energy will be

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a

4.9 J

b

9.8 J

c

19.6 J

d

14.7

answer is B.

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Detailed Solution

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$\begin{array}{l} P_{i} = P_{f} (no external force) \\ 0 .2 \times 10 = 10 \times v \\ v = 0 .2 m / \sec \\ Loss in K.E. = \frac{1}{2} \times (0 .2) \times 10^{2} - \frac{1}{2} \times 10 (0 .2)^{2} \\ = \frac{1}{2} \times 10 \times (0 .2) [10 - 0 .2] \\ = 9 .8 J \end{array}$

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