A bag of wheat weighs 200 kg. To what height should it be raised so that its potential energy becomes 9800 J? (g = 9.8ms^-2)

Given:
Mass of the bag, m = 200 kg
Potential energy, P.E = 9800J
Acceleration due to gravity, g = 9.8 ms^-2

To find the height of the bag to be raised, we have:
Potential energy, PE = mgh
Where m is the mass of the object and h is the height of the object.
Now,

PE = mgh
$\Rightarrow \mathrm{h}=\frac{\mathrm{P}.\mathrm{E}}{\mathrm{mg}}$
$\Rightarrow \mathrm{h}=\frac{9800}{200\times 9.8}$
$\Rightarrow \mathrm{h}=5 \mathrm{m}$
Hence, the bag of wheat should be raised to a height of 5 m.