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Q.

A Bakelite beaker has volume capacity of 500 cc at 30°C . When it is partially filled with Vm volume (at 30oC ) of mercury, it is found that the unfilled volume of the beaker remains constant as the temperature is varied. If γ(beaker) =6×106C1 and γ(mercury )=1.5×104C1 where γ is the coefficient of volume expansion, then V (in cc) is close to 

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answer is 20.

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Detailed Solution

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Given: V = 500 cc, T = 30°C
γbeaker =6×106/Cγmercuy =1.5×104/CNowV=V1+γbΔTV=bΔT and Vm=Vm1+γmΔTVm=mΔT

Since the volume of air not changing the change in volume of mercury and change in volume of Bakelite beaker are same.

∆V=∆Vm⇒ Vm=Vγbγm=500×6×1061.5×104=5×61.5=20cc

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