A balanced Wheatstone bridge is shown the values of currents i₁ and i₂ are

It is a balanced Wheatstone bridge

$$\begin{gathered} {\mathrm{R}}_1=2+4=6\mathrm{\Omega };{\mathrm{R}}_2=3+6=9\mathrm{\Omega } \\ {\mathrm{R}}_{12}=\frac{{\mathrm{R}}_1{\mathrm{R}}_2}{{\mathrm{R}}_1+{\mathrm{R}}_2}=\frac{6\left(9\right)}{15}=3.6\mathrm{\Omega } \\ \mathrm{i}=\frac{\mathrm{E}}{{\mathrm{R}}_{\text{total }}}=\frac{6}{{\mathrm{R}}_{12}+0.4}=\frac{6}{3.6+0.4};\frac{6}{4}=1.5\mathrm{A} \\ {\mathrm{i}}_1:{\mathrm{i}}_2=\frac{1}{{\mathrm{R}}_1}:\frac{1}{{\mathrm{R}}_2}=\frac{1}{6}:\frac{1}{9}=3:2 \\ {\mathrm{i}}_1=\frac{3}{5}\left(1.5\right)=0.9\mathrm{A};{\mathrm{i}}_2=\frac{2}{5}\left(1.5\right)=0.6\mathrm{A} \end{gathered}$$