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Q.

A ball A is projected from the ground such that its horizontal range is maximum. Another ball B is dropped from a height equal to the maximum range of A. The ratio of the time of flight of A to the time of fall of B is

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a

1 : √2

b

1 : 2

c

1 : 1

d

√2 :1

answer is C.

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Detailed Solution

θ = 450  as R max and R = u2 /g

\large T_A=\frac {2usin45}{g}=\frac{\sqrt2u}{g};T_B=\sqrt{\frac {2h}{g}}=\sqrt{\frac{2R}{g}}

as free fall body \large = \sqrt{\frac {2u^2}{g^2}}=\frac {\sqrt2\;u}{g}

TA : TB = 1 : 1

 

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