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A ball A is thrown up vertically with a speed u and at the same instant another ball B is released from a height h. At time t, the speed of A relative to B is

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u –gt

$\sqrt{(u^{2} - g t)}$

answer is A.

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Detailed Solution

At time t

Velocity of A, $v_{A} = u - g t u p w a r d$

Velocity of B, $v_{B} = u - g t d o w n w a r d$

If we assume that height h is smaller than or equal to maximum height reached by A then at every instant $v_{A} a n d v_{B}$ are in opposite direction.

$∴ v_{A B} = v_{A} + v_{B} = u - g t + g t$

(speeds in opposite directions get added)

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