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Q.

A ball ‘A’ moving with a speed of 90 m/s collides with another identical ball ‘B’ moving with a speed ‘V’ in the opposite direction. ‘A’ comes to rest after the collision. If the coefficient of restitution is 0.8, The speed ‘V’ of B before collision is 

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a

90 ms−1

b

22.5 ms−1

c

81 ms−1

d

10 ms−1

answer is A.

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Detailed Solution

m90+m−v=0+mv2
v2=90−v
0.8=v2−v190−−v=90−v−090+v,V=10m/s 

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