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A ball impinges directly on another ball at rest. The first ball is brought to rest by the impact. If half of the kinetic energy is lost by impact, the value of coefficient of restitution is $\frac{1}{n} .$ Then the value of $n$ is :

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answer is 2.

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Detailed Solution

$m_{1} v_{1} = m_{2} v_{2} v_{2} = e v_{1}$
loss of energy = initial kinetic energy – final kinetic energy
on applying these we will get $e = 1 / 2$

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