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A ball is dropped from rest time t=0 from certain height. A second ball is dropped from same height at time t=1 s. At what time, the distance between two balls become 10m?

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1.5s

1.25s

1.75s

answer is B.

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Detailed Solution

After 1s the the first ball will decent through a distance of 5m.

The first ball will have a speed of 10m/s.

And from the instant the second ball is dropped, the relative acceleration will be zero. And both the balls will just have a relative velocity of 10m/s and an initial separation of 5m.

So after 0.5s the separation will be 10m, that is at t = 1.5s

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