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A ball is dropped from the top of a high building with a constant acceleration of $9 .8 m / s^{2}$ . What will be its velocity after 2 seconds?

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9.8 m/s

19.6 m/s

29.4 m/s

39.2 m/s

answer is B.

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Detailed Solution

Acceleration $= 9.8 m s^{- 2}$
Initial velocity = 0
Time = 2s
Final velocity = u + at
= 9.8 $\times$ 2
= 19.6 m/s

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