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Q.

A ball is dropped from top of a building 100m high. At the same time another ball is thrown upwards with a velocity of $40 {ms}^{- 1}$ from the bottom of the building. The two balls will meet after.

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a

3 s

b

2.5 s

c

5 s

d

2 s

answer is B.

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Detailed Solution

$t = \frac{h}{u} = \frac{100}{40} = 2 .5 s$

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A ball is dropped from top of a building 100m high. At the same time another ball is thrown upwards with a velocity of 40 ms-1from the bottom of the building. The two balls will meet after.