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Q.

A ball is projected from the ground at an angle of $45^{\circ}$ with the horizontal surface. It reaches a maximum height of 200m and returns to the ground. Upon hitting the ground for the first time, it loses half of its kinetic energy. Immediately after the bounce, the velocity of the ball makes an angle of $30^{\circ}$ with the horizontal surface. The maximum height it reaches after the bounce, in metres, is _________.

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answer is 50.

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Detailed Solution

$h = \frac{u^{2} \sin^{2} θ}{2 g}$

= 50m

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A ball is projected from the ground at an angle of 45∘ with the horizontal surface. It reaches a maximum height of 200m and returns to the ground. Upon hitting the ground for the first time, it loses half of its kinetic energy. Immediately after the bounce, the velocity of the ball makes an angle of 30∘ with the horizontal surface. The maximum height it reaches after the bounce, in metres, is _________.