A ball is projected obliquely with a velocity 49 ms^–1 strikes the ground at a distance of  245 m from the point of projection. It remained in air for

Solution:

For projectile motion, the range is given by:
R = u cos θ × T

Where T is the time of flight.

For an oblique projectile, if we assume maximum range condition (45° angle):
Time of flight T can be calculated from:

Using the relation:
T = 2R / u (simplified for 45° projection)
T = (2 × 245) / 49
T = 490 / 49
T = 10 seconds

Answer: The ball remained in air for 10 seconds.