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Q.

A ball is projected upwards from the top of the tower with a velocity 50 m/ sec. making angle 30° with the horizontal. The height of the tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground.

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answer is 7.

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Detailed Solution

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Sy=uyt+12ayt2​⇒−70=50sin30t−12×(10)t2​⇒−70=25t−5t2⇒​5t2−25t−70=0⇒t2−5t−14=0​⇒t2−7t+2t−14=0⇒t=7sec

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