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Q.

A ball is projected vertically upward with a speed of 50 ms1. Then the speed at half of the maximum height is g=10ms2

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a

100 ms1

b

125ms1

c

35 ms1

d

45 ms1

answer is C.

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Detailed Solution

velocity of the particle at half of the maximum height is  v2u2=2as v2u2=2g.u24g v2u2=u22 v2=u2u22 v2=u22

v=u2 =502 g=10ms2 =35.3 v=35m/s

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