A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

When the balt is released from the top of tower n then ratio of distance covered by the balt in first, second and third second

${\mathrm{h}}_1:{\mathrm{h}}_{\mathrm{n}}:{\mathrm{h}}_{\mathrm{m}}=1:3:5$

$\text{ [Because }\left.h_n\propto (2n-1)\right]$

$\therefore$ Ratio of work done

mgh_I : mgh_II : mgh_II : mgh_III

= 1 : 3 : 5