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Q.

A ball is thrown vertically upward. It has a speed of 10 m/s when it has reached one half of its maximum height. How high does the ball rise ? Tiake g = 10 m/s2

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a

15 m

b

5 m

c

10 m

d

20 m

answer is B.

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Detailed Solution

The situation is shown in figure

Question Image

For part CB, we have
u =10 m/s2 and v=0
Now v2 = u2 -2gs
∴ 0 = (10)2 -2x10x(h/2)
or 10h =100 or h=10m

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