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Q.

A ball is thrown vertically upward with an initial velocity of 150m/s. The ratio of velocity after 3s and 5s is $\frac{x + 1}{x} .$ The value of $x$ is ____ ${{take, g=10 m/s}^{2}}$

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a

-5

b

10

c

6

d

5

answer is B.

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Detailed Solution

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After, 3s, $v_{3} = 150 - 10 \times 3 = 120 {ms}^{- 1}$

After 5s, $v_{5} = 150 - 10 \times 5 = 100 {ms}^{- 1}$

Ratio: $\frac{v_{3}}{v_{5}} = \frac{120}{100} = \frac{6}{5} = \frac{x + 1}{x} \Rightarrow x = 5$

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A ball is thrown vertically upward with an initial velocity of 150m/s. The ratio of velocity after 3s and 5s is x+1x. The value of x is ____{take, g=10 m/s2 }