A ball is thrown vertically upwards from the ground with a speed 35m/s. Find the distance travelled in 4^th second (g=10m/s²)

Distance travelled in 3.5seconds,  $S^1=35\times 3.5-1/2\times 10\times {\left(3.5\right)}^{2 }=61.25$ 
Distance travelled in 3 seconds , $S^{11}=35\times 3-1/2\times 10\times 3^2=60$  
Distance travelled from t = 3 to t = 3.5sec is 1.25 upwards distance travelled from t = 3.5 to t = 4 is 1.25 downwards