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Q.


A ball is thrown vertically upwards from the Question Image level with an initial velocity of Question Image. At the same instant an open platform elevator passes the Question Image level, moving upwards with a constant velocity of Question Image. Determine Question Image


1) The ball will meet the elevator in ____ m


2) The relative velocity of the ball with respect to the elevator when the ball hits the elevator ____ m/s.


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Detailed Solution

Concept- In this question consider the Initial velocity of ball Question Image, initial level of the ball from the ground Question ImageQuestion Image, velocity of elevator Question Image (constant velocity, initial level of elevator from the ground Question Image. Then
use a second equation of motion to get the distance travelled by the ball and the elevator. The distance travelled by the elevator must be equal to the distance travelled by the ball to get the first part. For the second part use the concept that the relative velocity of the ball is the difference between the final velocity of the ball and the velocity of the elevator.
Formula used Question Image(A)Initial velocity of ball Question ImageInitial position of ball Question ImageAcceleration Question ImageSubstituting these values in the equation for uniformly accelerated motion we get
Question ImageQuestion ImageQuestion ImageQuestion ImageNow,
Initial velocity of elevator Question ImageQuestion ImageQuestion ImageWhen ball hit the elevator then
Question ImageQuestion ImageQuestion ImageQuestion ImageQuestion ImageQuestion ImagePutting in (1)
Question ImageQuestion Image (B)Relative velocity of ball wrt the elevator
Question ImageWhen the ball hits the elevator at time Question Image we have
Question ImageQuestion ImageThe negative sign means that the ball is observed from the elevator to the moving in the negative sense(downward).
Hence, the answer is 1)12.30m
2)-19.81m/s
 
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