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Q.

A ball is thrown vertically upwards with a velocity of 19.6 ms-1 from the top of a tower. The ball strikes the ground after 6 s. The height from the ground up to which the ball can rise will be k5m. The value of k is ....... (use g= 9.8 m/s2)

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answer is 392.

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Detailed Solution

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ta = ug = 19.69.8 = 2s

td = 6-2s = 2hmaxg

hmax = 16 × 9.82 = 3925

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