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A ball is thrown vertically upwards with a velocity of $49 m / s$ . Calculate the maximum height to which it rises

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980 m

163 m

200 m

122.5 m

answer is D.

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Detailed Solution

The maximum height is

122.5 m

.
Given data in the problem,
The velocity of ball thrown upwards,

u = 49 m / s

Acceleration due to gravity,

g = 9.8 {ms}^{- 2}

By using the third equation of motion,

v^{2} - u^{2} = 2 gs

Where,

v

= final velocity

u

= initial velocity

g

= gravity
s = height

\Rightarrow 0^{2} - 49^{2} = 2 \times 9.8 \times s

\Rightarrow s = \frac{49 \times 49}{2 \times 9.8}

\Rightarrow s = 122.5 m

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