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A ball moves over a fixed track as shown in the figure. From $A t o B$ the ball rolls without slipping. Surface $B C$ is frictionless $K_{A}, K_{B} a n d K_{C}$ are kinetic energies of the ball at $A, B a n d C$ respectively. Then :

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$h_{A} < h_{C}; K_{B} > K_{C}$

$h_{A} = h_{C}; K_{B} = K_{C}$

$h_{A} > h_{C}; K_{B} > K_{C}$

$h_{A} > h_{C}; K_{C} > K_{A}$

answer is A, B.

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Detailed Solution

$K + U = c o n s \tan t$

or $K_{A} + U_{A} = K_{C} + U_{C}$ = $K_{B} + U_{B}$

If $h_{A} > h_{c}, t h e n U_{A} > U_{C} a n d s o K_{A} < K_{C}$

When

$U_{B} < U_{C} a n d s o K_{B} > K_{C}$

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