Q.

A ball of mass 0.2 kg rests on a vertical post of height 5 m. A bullet of mass 0.01 kg, travelling with a velocity ν m/s in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance of 100 m from the foot of the post. The initial velocity ν of the bullet is

Question Image

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

500 m/s

b

2502m/s

c

250 m/s

d

400 m/s

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Time taken by the bullet and ball to strike the ground is
t=2hg=2.510=1s
Let ν1 and ν2 be the velocities of ball and bullet after
collision. Then applying,
x = νt
We have, 20=v11 or v1=20m/s
100=v2.1 or v2=100m/s
Now, from conservation of linear momentum before and after collision we have,
0.01v=(0.2.20)+(0.01.100)
On solving, we get
v = 500 m / s.

Watch 3-min video & get full concept clarity

hear from our champions

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon