A ball of mass 1 kg is thrown vertically upwards and returns to the ground after 3 seconds. Another ball, thrown at 60° with vertical also stays in air for the same time before it touches the ground. The ratio of the two heights are :

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2 : 1

1 : 3

1 : 2

1 : 1

answer is B.

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Detailed Solution

$\begin{array}{l} T = t_{a} + t_{d} = 3 s \\ t_{a} = t_{d} = \frac{T}{2} = 1.5 S \\ H_{1} = \frac{1}{2} g t_{d}^{2} \\ H_{2} = \frac{u^{2} \sin^{2} θ}{2 g} = \frac{1}{2} g t_{d}^{2} \\ H_{1} : H_{2} = 1 : 1 \end{array}$

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