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A ball of mass 1kg strikes a heavy platform moving upwards with a velocity of 5m/s elastically. The speed of the ball just before collision is 10m/s downwards. The impulse imparted by the platform on the ball is

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5 N-S

10 N-S

20 N-S

30 N-S

answer is D.

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Detailed Solution

For elastic collision

$V_{2} - V_{1} = u_{1} - u_{2}$

$5 - V_{1} = (- 10) - 5$

$V_{1} = 20 m / s$

impulse

$= m (V_{1} - u_{1}) = [20 - (- 10)] = 30 N - S$

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