A ball of mass 2 kg strikes a floor as shown in figure. For this situation mark the correct statement(s)

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The impulse experienced by ball during the collision is acting along the $+ v e$ y- direction and is having a magnitude of 50 $N - S .$

Floor is smooth

The impulse experienced by ball during the collision is $50 kg . m / s$ vertically downward.

Coefficient of restitution between floor and ball is $\frac{9}{16}$

answer is A, B, C.

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Detailed Solution

Here the component of momentum along the surface remains constant, it means these is no component of impulse along the surface. So impulse is acting along the $+ v e$ y-axis $| \hat{j} | = | {\vec{P}}_{t} - {\vec{P}}_{i} | = 50 N - S$ along $+ v e$ y-axis $e = \frac{15 \cos 53^{°}}{20 \cos 37^{°}} = \frac{9}{16}$

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