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A ball of mass 200g is on one end of a string of length 20cm. It is revolved in a horizontal circle at a angular frequency of 6 rpm the angular velocity is

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a

$\frac{7 π}{5} {rad s}^{- 1}$

b

$\frac{3 π}{5} {rad s}^{- 1}$

c

$\frac{π}{5} {rad s}^{- 1}$

d

$\frac{2 π}{3} {rad s}^{- 1}$

answer is A.

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Detailed Solution

mass = 200 g

length = 20 cm

$ω =$ 6 revolution per minute 1 revolution $= 2 π^{c}$ 1 min = 60 s

$ω = \frac{2 π^{c} n}{T} =2 π^{c} \times \frac{6}{60} = \frac{π}{5} rad/s$

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