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A ball of mass $2 k g$ is at rest on a horizontal smooth surface. Another ball of same mass hit the first ball at an angle of $60^{\circ}$ with the horizontal. At the time of collision velocity of second ball is $20 m / s$ . If collision is perfectly inelastic and after collision both the balls will stick together, then the speed of combined ball is----- $m / \sec$

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answer is 5.

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Detailed Solution

$∴$ Momentum along the tangential line remains constant, then $2 \times 20 \cos 60^{\circ} = 4 \times v$

$v = 5 m / s$

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