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A ball of mass 50 g moving with a velocity of 10 ms^-1 is hit by a bat and the ball retraces back with a velocity of 20 ms^-1. Then the impulse on the bat is

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15 kg ms^-1

0.15 kg ms^-1

150 kg ms^-1

1.5 kg ms^-1

answer is D.

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Detailed Solution

$|J| = |∆ p| = |0.050 \times (10 + 20)| = 1.5 kg m / s$

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