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Q.

A ball of mass 5kg hangs from a spring of force constant k N/m and oscillates with certain time period. If the ball is removed, the spring shortens by:

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a

Kgm

b

5gKm

c

mgk

d

2mgk

answer is B.

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Detailed Solution

Question Image

When the ball is in equilibrium, Mg = kxs where xs = static deflection of the spring.

Shortening of spring = xs = Mg/K = 5gK

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