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Q.

A ball of mass (m) 0.5 kg is attached to the end of a string having length (L) 0.5 m. The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324N. The maximum possible value of angular velocity of ball (in radian/s) 

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answer is 36.

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Detailed Solution

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Tsinθ=mRω2  ……. (1) Tcosθ=mg   ……. (2)

Dividing (2) by (1)  ⇒    Tanθ=ω2Rg⇒ω=RgTnθ
For  'ω' max  θ→max, θ=900
T=mRω2=mLω2 ω=Tm2=3240.5×0.5=36   rad/sec

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