A ball of mass 'm' approaches a wall of mass 'M'(>>m) with speed 4 m/s along the normal to the wall. The speed of wall is 1 m/s towards the ball. The speed of the ball after an elastic collision with the wall is

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5 m/s away from the wall

9 m/s away from the wall

6 m/s away from the wall

3 m/s away from the wall

answer is C.

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Detailed Solution

$As it is an elastic collision v_{2} - v_{1} = u_{1} - u_{2} u_{1} = v_{1} i . e . heavier mass velocity does not change So v_{2} = 2 u_{1} - u_{2} v_{2} = 2 \times 1 + 4 as they are moving in opposite direction v_{2} = 6 m / s away from the wall .$

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