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Q.

A ball of mass ‘m’ is thrown in air with speed $v_{1}$ from a height $h_{1}$ and it is caught at a height $h_{2} > h_{1}$ when its speed becomes $v_{2}$ . Find the work done on the ball by air resistance.

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a

$mg (h_{2} - h_{1}) + \frac{1}{2} m ({v_{2}}^{2} - {v_{1}}^{2})$

b

$mg (h_{2} - h_{1})$

c

$\frac{1}{2} m ({v_{2}}^{2} - {v_{1}}^{2})$

d

$mg (h_{2} - h_{1}) - \frac{1}{2} m ({v_{2}}^{2} - {v_{1}}^{2})$

answer is A.

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Detailed Solution

$W_{mg} + W_{air} = ∆ K . E .$

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