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A ball of mass m moving with velocity v strikes the bob of pendulum at rest. The mass of the bob is also m. If the collision is perfectly inelastic, the height to which the bob will rise is given by $h = \frac{v^{2}}{x g},$ then x = ?

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answer is 8.

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Detailed Solution

From LCLM $2 m V^{1} = m V, V^{1} = \frac{V}{2}$

By LCE $2 m g h = \frac{1}{2} 2 m {(\frac{V^{1}}{2})}^{2}, h = \frac{V^{2}}{8 g}$

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