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A ball of mass $2 k g$ is connected to a string of length $1 m$ and made to move in a horizontal circle on a smooth friction less table with a constant speed of $2 m / s$ . The other end of the string is connected to a fixed peg on the table. Find the magnitude of the impulse exerted by the string on the ball in half a revolution.

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$0$

$8 N - s e c$

$4 N - s e c$

$2 \sqrt{2} N - s e c$

answer is B.

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Detailed Solution

$\overset{⇀}{I} = ∆ (m \overset{⇀}{v}) = m (\overset{⇀}{v_{f}} - \overset{⇀}{v_{i}}) = 2 \times (- 2 - 2) = - 8 N s e c$

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