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A ball of mass $500 g m$ strikes a wall with a velocity of $10 m s^{- 1}$ at an angle $30^{0}$ with the wall and rebounds with the same speed at the same angle with the wall. The change in momentum of the ball is, (in kg ms^–1)

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answer is C.

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Detailed Solution

$Δ P = 2 m v \sin θ = 2 \times 500 \times 10^{- 3} \times 10 \times \frac{1}{2}$

$= 5 k g m s^{- 1}$

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