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Q.

A ball of weight 0.1 kg coming with speed 30 m/s strikes with a bat and returns in opposite direction with speed 40 m/s, then the impulse is (Taking final velocity as positive)

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a

0.1×(40)−0.1×(20)

b

−0.1×(40)−0.1×(30)

c

0.1×(40)+0.1×(−30)

d

0.1×(40)−0.1×(−30)

answer is B.

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Detailed Solution

Impulse = change in momentum 

mv2−mv1=0.1×40−0.1×(−30)

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