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A ball projected from ground. Its range and maximum height attained are R and H. If wind blows horizontally in the direction of projection with an acceleration g/4, its range will be

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$R + \frac{H}{2}$

$R + H$

$2 R + H$

$2 (R + H)$

answer is B.

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Detailed Solution

$R^{1} = u_{x} T + \frac{1}{2} a_{x} T^{2} = u_{x} T + \frac{1}{2} (\frac{g}{4}) T^{2} = R + H$

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