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Q.

A ball thrown horizontally with a velocity of 8 m/s from the top of the building strikes the ground 12m away from the building. What is the height of the building? (g=9.8 m/s²)

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a

7 m

b

11 m

c

8 m

d

10 m

answer is A.

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Detailed Solution

$\begin{array}{l} g i v e n i n i t i a l v e l o c i t y h o r i z o n t a l l y = u_{x} = 8 m / s; R a n g e = R = 12 m \\ R = U t \\ \Rightarrow t = \frac{R}{U} \\ t = \frac{12}{8} \\ Now height of building= h = \frac{1}{2} g t^{2} \\ h = \frac{1}{2} (9.8) {(\frac{12}{8})}^{2} = 11.25 m \end{array}$

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