AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Q.

A ball thrown up vertically returns to the thrower after $6 s$ . The position of the ball after $4 s$ is ____ $m$ .

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

A ball thrown up vertically returns to the thrower after

6 s

. The position of the ball after 4 s is

4.9 m

.
The equation of motion of an object forms a relation between displacement and velocity and acceleration and time. These equations are usually for the one-dimensional motion of an object.
Here, as the ball is thrown upwards and comes down, so the final velocity of the ball is zero. Also, the ball takes

6 s

to go up and to come down. So, only to go up, it takes

3

seconds

(\frac{6}{2})

. Now we can calculate the position of the ball from the top after

1 s

(as

3 + 1 = 4 s

).
For that, we can use the formula,

\Rightarrow h = ut + \frac{1}{2} g t^{2}

….(1)
Here, initial velocity

u = 0

,
Time

t = 1 s

,
Gravitational acceleration

g = 9.8 m / s^{2}

By putting these values in equation (1),

\Rightarrow h = 0 \times 1 + \frac{1}{2} \times 9.8 \times 1^{2}

\Rightarrow h = 4.9 \times 1

\Rightarrow h = 4.9 m

Hence, the ball will be at

4.9 m

below the maximum height it reached.

Watch 3-min video & get full concept clarity

courses

No courses found

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

best study material, now at your finger tips!

live classes
progress tracking
24x7 mentored guidance
study plan analysis

download the app

gplay

mentor

Download the App

gplay

personalised 1:1 online tutoring