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A balloon is moving along with constant upward acceleration of 1 $m / s^{2}$ . A stone is thrown from the balloon downwards with speed 10 m/s with respect to the balloon. At the time of projection balloon is at height 120 m from the ground and is moving with speed 20 m/s. Find the height of balloon from ground when the stone falls on the ground.

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258 m

120 m

358 m

138 m

answer is B.

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Detailed Solution

-120 = 10t $- \frac{1}{2} 10 t^{2}$

$t^{2} - 2 t - 24 = 0$

t = 6 sec

$h = 20 (6) + \frac{1}{2} (1) {(6)}^{2} = 138 m$

$Total height = 138 + 120 = 258 m$

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