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A balloon rising vertically upwards with a constant velocity of $15 m s^{- 1}$ . When it is at a height of 50 m above the ground, a stone is dropped from it. Find the time taken by the stone to hit ground

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Detailed Solution

When a stone is dropped it possesses a velocity of $15 m s^{- 1}$
Upwards $h = - u t + \frac{1}{2} g t^{2} \Rightarrow 50 = - 15 + 5 t^{2}$

$t^{2} - 3 t - 10 = 0 \Rightarrow (t - 5) (t + 2) = 0 \Rightarrow t = 5 \sec$

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