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A bar magnet has a magnetic moment equal to 5 × 10^–5 Weber × metre. It is suspended in a magnetic field which has a magnetic induction (B) equal to $8 π \times 10^{- 4}$ tesla. The magnet vibrates with a period of vibration equal to15 seconds. The moment of inertia of the magnet is:

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7.165X10^-7 kgm²

5.62 x10^-13 kgm²

11.25 x10 ^-13 kgm²

0.57 x 10 ^-13 kgm²

answer is A.

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Detailed Solution

$I = \frac{{MBT}^{2}}{4 π^{2}}$

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