A bar magnet has magnetic dipole moment M. Its initial position is parallel to the direction of uniform magnetic field B. In this position, the magnitudes of torque and force acting on it respectively are –

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0 and 0

|M X B| and 0

0 and MB

MB and MB

answer is C.

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Detailed Solution

$τ = M.B \sin 0^{\circ} \Rightarrow τ = 0$
Forces on poles will be equal and opposite as shown in diagram. So net force is also zero.
[Magnitude of any force =F=m . B ]
[Where m is pole strength]

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